Y-4=1/2(x+1)^2

Simple and best practice solution for Y-4=1/2(x+1)^2 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Solution for Y-4=1/2(x+1)^2 equation:



-4=1/2(Y+1)^2
We move all terms to the left:
-4-(1/2(Y+1)^2)=0
Domain of the equation: 2(Y+1)^2)!=0
Y∈R
We multiply all the terms by the denominator
-(1-4*2(Y+1)^2)=0
We calculate terms in parentheses: -(1-4*2(Y+1)^2), so:
1-4*2(Y+1)^2
determiningTheFunctionDomain -4*2(Y+1)^2+1
Wy multiply elements
-8Y(Y+1
Back to the equation:
-(-8Y(Y+1)
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
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We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
-8Y(Y+1
We calculate terms in parentheses: -(-8Y(Y+1), so:
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We calculate terms in parentheses: -(-8Y(Y+1), so:
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